What is the integral from 3 to 9 of sqrt(1+x^4+2x^2) ?

The integral from 3 to 9 of sqrt(1+x^4+2x^2) is 240

integral from 3 to 9 of sqrt(1+x^4+2x^2)

\int_{3}^{9} 1 + x^{4} + 2 x^{2} d x

240

Solution steps

\int_{3}^{9} 1 + x^{4} + 2 x^{2} d x

Factor

1 + x^{4} + 2 x^{2} : (x^{2} + 1)^{2}

= \int_{3}^{9} (x^{2} + 1)^{2} d x

Apply exponent rule:

a^{2} = ∣ a ∣

= \int_{3}^{9} (x^{2} + 1)^{2} d x

Eliminate Absolutes

= \int_{3}^{9} (x^{2} + 1)^{2} d x

Apply exponent rule:

a^{2} = ∣ a ∣

= \int_{3}^{9} (x^{2} + 1) d x

Eliminate Absolutes

= \int_{3}^{9} x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{3}^{9} x^{2} d x + \int_{3}^{9} 1 d x

\int_{3}^{9} x^{2} d x = 234

\int_{3}^{9} 1 d x = 6

= 234 + 6

Simplify

= 240

y = 3 1 + 7 x

\frac{d}{d x} (18 x^{2})

\frac{d}{d x} (8 x^{2} + 2 x - 3)

\int_{1}^{4} x^{2} + \frac{1}{4 x ^{2}} d x

\int \frac{e ^{x}}{a + b e ^{x}} d x

What is the integral from 3 to 9 of sqrt(1+x^4+2x^2) ?
The integral from 3 to 9 of sqrt(1+x^4+2x^2) is 240