What is the integral from-1 to 3 of 6x^2 ?

The integral from-1 to 3 of 6x^2 is 56

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integral from-1 to 3 of 6x^2

\int_{- 1}^{3} 6 x^{2} d x

56

Solution steps

\int_{- 1}^{3} 6 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{- 1}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{3}

= 6 [\frac{x ^{3}}{3}]_{- 1}^{3}

Compute the boundaries:

\frac{28}{3}

= 6 \cdot \frac{28}{3}

Simplify

= 56

e^{- x^{2}}

\frac{e ^{x}}{6 x ^{2} + 7}

f (x) = 5 x^{\frac{3}{2}} - 2 x, (1, 3)

n = 0 \sum \infty \frac{0. 5 ^{n}}{n !}

\int 8 x^{\frac{1}{3}} d x

What is the integral from-1 to 3 of 6x^2 ?
The integral from-1 to 3 of 6x^2 is 56