What is the integral of xe^{6x^2} ?

The integral of xe^{6x^2} is 1/12 e^{6x^2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of xe^{6x^2}

\int x e^{6 x^{2}} d x

\frac{1}{12} e^{6 x^{2}} + C

Solution steps

\int x e^{6 x^{2}} d x

Apply u-substitution

: \int \frac{e ^{u}}{12} d u

= \int \frac{e ^{u}}{12} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{12} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{12} e^{u}

Substitute back

u = 6 x^{2}

= \frac{1}{12} e^{6 x^{2}}

Add a constant to the solution

= \frac{1}{12} e^{6 x^{2}} + C

\int \frac{1}{sin ( x ) + tan ( x )} d x

\frac{d}{d x} (i sin (x))

\frac{d}{d x} (arccot (10 x))

y^{^{''}} = (y^{^{'}})^{2}

\int_{0}^{l n (9)} x e^{x} d x

What is the integral of xe^{6x^2} ?
The integral of xe^{6x^2} is 1/12 e^{6x^2}+C