What is the derivative of arccot(10x) ?

The derivative of arccot(10x) is -(10)/(100x^2+1)

What is the first derivative of arccot(10x) ?

The first derivative of arccot(10x) is -(10)/(100x^2+1)

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\frac{d}{d x} (arccot (10 x))

- \frac{10}{100 x ^{2} + 1}

Solution steps

\frac{d}{d x} (arccot (10 x))

Apply the chain rule:

- \frac{1}{( 10 x ) ^{2} + 1} \frac{d}{d x} (10 x)

= - \frac{1}{( 10 x ) ^{2} + 1} \frac{d}{d x} (10 x)

\frac{d}{d x} (10 x) = 10

= - \frac{1}{( 10 x ) ^{2} + 1} \cdot 10

Simplify

- \frac{1}{( 10 x ) ^{2} + 1} \cdot 10 : - \frac{10}{100 x ^{2} + 1}

= - \frac{10}{100 x ^{2} + 1}

y^{^{''}} = (y^{^{'}})^{2}

\int_{0}^{l n (9)} x e^{x} d x

x (\frac{d y}{d x}) + y = e^{x}, y (1) = 2

\frac{d}{d x} (ln (x^{\frac{1}{3}}))

\frac{d}{d x} (cos (x (1 + sin (x))^{10}))

What is the derivative of arccot(10x) ?
The derivative of arccot(10x) is -(10)/(100x^2+1)
What is the first derivative of arccot(10x) ?
The first derivative of arccot(10x) is -(10)/(100x^2+1)