What is the integral from 2 to 3 of t^2 ?

The integral from 2 to 3 of t^2 is 19/3

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integral from 2 to 3 of t^2

\int_{2}^{3} t^{2} d t

\frac{19}{3}

Decimal Notation

6.33333 \dots

Solution steps

\int_{2}^{3} t^{2} d t

Apply the Power Rule

: [\frac{t ^{3}}{3}]_{2}^{3}

= [\frac{t ^{3}}{3}]_{2}^{3}

Compute the boundaries:

\frac{19}{3}

= \frac{19}{3}

f (x) = (- x^{2} + 3)^{2}

f (x) = (x + 2) (2 x^{2} - 3)

arcsin (x), 0

\int (6 x^{2}) (e^{x^{3} + 2}) d x

9 cos (x)

What is the integral from 2 to 3 of t^2 ?
The integral from 2 to 3 of t^2 is 19/3