What is the derivative of f(x)=(-x^2+3)^2 ?

The derivative of f(x)=(-x^2+3)^2 is -4x(-x^2+3)

What is the first derivative of f(x)=(-x^2+3)^2 ?

The first derivative of f(x)=(-x^2+3)^2 is -4x(-x^2+3)

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derivative of

f (x) = (- x^{2} + 3)^{2}

- 4 x (- x^{2} + 3)

Solution steps

\frac{d}{d x} ((- x^{2} + 3)^{2})

Apply the chain rule:

2 (- x^{2} + 3) \frac{d}{d x} (- x^{2} + 3)

= 2 (- x^{2} + 3) \frac{d}{d x} (- x^{2} + 3)

\frac{d}{d x} (- x^{2} + 3) = - 2 x

= 2 (- x^{2} + 3) (- 2 x)

Simplify

= - 4 x (- x^{2} + 3)

f (x) = (x + 2) (2 x^{2} - 3)

arcsin (x), 0

\int (6 x^{2}) (e^{x^{3} + 2}) d x

9 cos (x)

y = - x^{2} + 16, y = 0, x = - 2, x = 3

What is the derivative of f(x)=(-x^2+3)^2 ?
The derivative of f(x)=(-x^2+3)^2 is -4x(-x^2+3)
What is the first derivative of f(x)=(-x^2+3)^2 ?
The first derivative of f(x)=(-x^2+3)^2 is -4x(-x^2+3)