What is the solution for (7x+2y)y^'=-2x-7y ?

The solution for (7x+2y)y^'=-2x-7y is y=(-7x+sqrt(45x^2+c_{1)})/2 ,y=(-7x-sqrt(45x^2+c_{1)})/2

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(7x+2y)y^'=-2x-7y

(7 x + 2 y) y^{^{'}} = - 2 x - 7 y

y = \frac{- 7 x + 45 x ^{2} + c _{1}}{2}, y = \frac{- 7 x - 45 x ^{2} + c _{1}}{2}

Solution steps

(7 x + 2 y) y^{'} (x) = - 2 x - 7 y

Solve exact ODE:

y = \frac{- 7 x + 45 x ^{2} + c _{1}}{2}, y = \frac{- 7 x - 45 x ^{2} + c _{1}}{2}

y = \frac{- 7 x + 45 x ^{2} + c _{1}}{2}, y = \frac{- 7 x - 45 x ^{2} + c _{1}}{2}

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What is the solution for (7x+2y)y^'=-2x-7y ?
The solution for (7x+2y)y^'=-2x-7y is y=(-7x+sqrt(45x^2+c_{1)})/2 ,y=(-7x-sqrt(45x^2+c_{1)})/2