What is the solution for (d^2y)/(dx^2)+8(dy)/(dx)+16y=0 ?

The solution for (d^2y)/(dx^2)+8(dy)/(dx)+16y=0 is y=c_{1}e^{-4x}+c_{2}xe^{-4x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)+8(dy)/(dx)+16y=0

\frac{d ^{2} y}{d x ^{2}} + 8 \frac{d y}{d x} + 16 y = 0

y = c_{1} e^{- 4 x} + c_{2} x e^{- 4 x}

Solution steps

\frac{d ^{2} y}{d x ^{2}} + 8 \frac{d y}{d x} + 16 y = 0

Solve linear ODE:

y = c_{1} e^{- 4 x} + c_{2} x e^{- 4 x}

y = c_{1} e^{- 4 x} + c_{2} x e^{- 4 x}

cos (π x), 0

\frac{16}{x}

\frac{\partial}{\partial y} (3 x^{2})

\frac{d}{d x} (x^{5} - 5 x)

\int \frac{x ^{2}}{x + 4} d x

What is the solution for (d^2y)/(dx^2)+8(dy)/(dx)+16y=0 ?
The solution for (d^2y)/(dx^2)+8(dy)/(dx)+16y=0 is y=c_{1}e^{-4x}+c_{2}xe^{-4x}