What is expand-(2x)/((x^2+4)^2) ?

The solution to expand-(2x)/((x^2+4)^2) is -(2x)/(x^4+8x^2+16)

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expand-(2x)/((x^2+4)^2)

expand

- \frac{2 x}{( x ^{2} + 4 ) ^{2}}

- \frac{2 x}{x ^{4} + 8 x ^{2} + 16}

Solution steps

- \frac{2 x}{( x ^{2} + 4 ) ^{2}}

(x^{2} + 4)^{2} = x^{4} + 8 x^{2} + 16

= - \frac{2 x}{x ^{4} + 8 x ^{2} + 16}

f (x) = \frac{8}{x}

x \to - π lim ((x + π) cot (x))

\int sin^{7} (y) d y

\int \frac{3}{35} x^{2} d x

y^{^{'''}} + 2 y^{^{''}} - 13 y^{^{'}} + 10 y = 0

What is expand-(2x)/((x^2+4)^2) ?
The solution to expand-(2x)/((x^2+4)^2) is -(2x)/(x^4+8x^2+16)