What is the integral of 7/(sqrt(1+x^2)) ?

The integral of 7/(sqrt(1+x^2)) is 7ln|sqrt(x^2+1)+x|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 7/(sqrt(1+x^2))

\int \frac{7}{1 + x ^{2}} d x

7 ln x^{2} + 1 + x + C

Solution steps

\int \frac{7}{1 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = ln x^{2} + 1 + x

= 7 ln x^{2} + 1 + x

Add a constant to the solution

= 7 ln x^{2} + 1 + x + C

x^{2} ln (7 x)

f (x) = x + 1, at x = 8

\int (x^{2} + 2 x)^{3} d x

t sin (t)

\frac{d}{d x} (\frac{2}{( 3 x ^{2} + 7 ) ^{2}})

What is the integral of 7/(sqrt(1+x^2)) ?
The integral of 7/(sqrt(1+x^2)) is 7ln|sqrt(x^2+1)+x|+C