What is the derivative of asin(x)+bcos(x) ?

The derivative of asin(x)+bcos(x) is acos(x)-bsin(x)

What is the first derivative of asin(x)+bcos(x) ?

The first derivative of asin(x)+bcos(x) is acos(x)-bsin(x)

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derivative of

a sin (x) + b cos (x)

a cos (x) - b sin (x)

Solution steps

\frac{d}{d x} (a sin (x) + b cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a sin (x)) + \frac{d}{d x} (b cos (x))

\frac{d}{d x} (a sin (x)) = a cos (x)

\frac{d}{d x} (b cos (x)) = - b sin (x)

= a cos (x) - b sin (x)

f (x) = x + 1 + \frac{1}{x ^{2}}

\frac{d}{d x} (tan^{3} (2 x))

\int \frac{7}{2 x ^{\frac{9}{4}}} d x

y^{^{''}} - 8 y^{^{'}} + 16 y = t^{- 9} e^{4 t}

n \to \infty lim (\frac{n}{6})

What is the derivative of asin(x)+bcos(x) ?
The derivative of asin(x)+bcos(x) is acos(x)-bsin(x)
What is the first derivative of asin(x)+bcos(x) ?
The first derivative of asin(x)+bcos(x) is acos(x)-bsin(x)