What is the derivative of x^2+3x+sqrt(4) ?

The derivative of x^2+3x+sqrt(4) is 2x+3

What is the first derivative of x^2+3x+sqrt(4) ?

The first derivative of x^2+3x+sqrt(4) is 2x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{2} + 3 x + 4)

2 x + 3

Solution steps

\frac{d}{d x} (x^{2} + 3 x + 4)

Simplify

x^{2} + 3 x + 4 : x^{2} + 3 x + 2

= \frac{d}{d x} (x^{2} + 3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 2 x + 3 + 0

Simplify

= 2 x + 3

t \cdot \frac{d y}{d t} + 37 y = \frac{1}{t}

x^{2} - 1

\int \frac{1}{y - 4} d y

4 y^{^{''}} - 40 y^{^{'}} + 96 y = 5 sin (2 x)

\int_{1}^{e^{2}} x^{3} ln (x) d x

What is the derivative of x^2+3x+sqrt(4) ?
The derivative of x^2+3x+sqrt(4) is 2x+3
What is the first derivative of x^2+3x+sqrt(4) ?
The first derivative of x^2+3x+sqrt(4) is 2x+3