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Popular >

y^'=-sin(pix)

Solution

y^{^{'}} = - sin (π x)

Solution

y = \frac{1}{π} cos (π x) + c_{1}

Solution steps

y^{'} (x) = - sin (π x)

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - sin (π x) d x

\int - sin (π x) d x = \frac{1}{π} cos (π x) + c_{1}

y = \frac{1}{π} cos (π x) + c_{1}

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Frequently Asked Questions (FAQ)

What is the solution for y^'=-sin(pix) ?
The solution for y^'=-sin(pix) is y= 1/pi cos(pix)+c_{1}