What is the derivative of 2cos(x+sin^2(x)) ?

The derivative of 2cos(x+sin^2(x)) is -2sin(x)+sin(2x)

What is the first derivative of 2cos(x+sin^2(x)) ?

The first derivative of 2cos(x+sin^2(x)) is -2sin(x)+sin(2x)

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\frac{d}{d x} (2 cos (x) + sin^{2} (x))

- 2 sin (x) + sin (2 x)

Solution steps

\frac{d}{d x} (2 cos (x) + sin^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (x)) + \frac{d}{d x} (sin^{2} (x))

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

\frac{d}{d x} (sin^{2} (x)) = sin (2 x)

= - 2 sin (x) + sin (2 x)

\frac{\partial}{\partial x} (∣ x y ∣^{\frac{1}{2}})

y = \frac{1}{x}, (2, \frac{1}{2})

\frac{7}{s ^{2} + 49}

\frac{d}{d x} (arcsec (3 x))

\int 5 x^{2} - \frac{4}{x} + a d x

What is the derivative of 2cos(x+sin^2(x)) ?
The derivative of 2cos(x+sin^2(x)) is -2sin(x)+sin(2x)
What is the first derivative of 2cos(x+sin^2(x)) ?
The first derivative of 2cos(x+sin^2(x)) is -2sin(x)+sin(2x)