What is the derivative of (ln(x)/2+2) ?

The derivative of (ln(x)/2+2) is 1/(2x)

What is the first derivative of (ln(x)/2+2) ?

The first derivative of (ln(x)/2+2) is 1/(2x)

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\frac{d}{d x} (\frac{ln ( x )}{2} + 2)

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (\frac{ln ( x )}{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{ln ( x )}{2}) + \frac{d}{d x} (2)

\frac{d}{d x} (\frac{ln ( x )}{2}) = \frac{1}{2 x}

\frac{d}{d x} (2) = 0

= \frac{1}{2 x} + 0

Simplify

= \frac{1}{2 x}

\int (2 x - 40) ln (x - 20) d x

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\frac{d}{d x} [f (x^{2})] = x^{5}

What is the derivative of (ln(x)/2+2) ?
The derivative of (ln(x)/2+2) is 1/(2x)
What is the first derivative of (ln(x)/2+2) ?
The first derivative of (ln(x)/2+2) is 1/(2x)