What is the derivative of 3x^2-2sqrt(x) ?

The derivative of 3x^2-2sqrt(x) is 6x-1/(sqrt(x))

What is the first derivative of 3x^2-2sqrt(x) ?

The first derivative of 3x^2-2sqrt(x) is 6x-1/(sqrt(x))

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\frac{d}{d x} (3 x^{2} - 2 x)

6 x - \frac{1}{x}

Solution steps

\frac{d}{d x} (3 x^{2} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = \frac{1}{x}

= 6 x - \frac{1}{x}

\frac{\partial}{\partial x} (x + y cos (y))

\int_{0}^{π} 2 x^{2} sin (\frac{1}{2} x) d x

\frac{4 x ^{2} + 2 x + 2}{x}

\frac{d}{d x} (x^{2} - 7 x + 2)

\frac{d}{d x} (\frac{( x + 1 - 1 )}{x})

What is the derivative of 3x^2-2sqrt(x) ?
The derivative of 3x^2-2sqrt(x) is 6x-1/(sqrt(x))
What is the first derivative of 3x^2-2sqrt(x) ?
The first derivative of 3x^2-2sqrt(x) is 6x-1/(sqrt(x))