What is the limit as x approaches 0 of 1/(3x) ?

The limit as x approaches 0 of 1/(3x) is diverges

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limit as x approaches 0 of 1/(3x)

x \to 0 lim (\frac{1}{3 x})

diverges

Solution steps

x \to 0 lim (\frac{1}{3 x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{3 x}) = \infty

x \to 0 - lim (\frac{1}{3 x}) = - \infty

= diverges

x y^{^{'}} - y = x ln (x)

4^{x} x^{4}

x (x + 1) (\frac{d y}{d x}) + x y = 1

(x^{2} + y^{2}) d x + 6 x y d y = 0

\frac{1}{( s ^{2} + 4 ) ( s ^{2} - 4 )}

What is the limit as x approaches 0 of 1/(3x) ?
The limit as x approaches 0 of 1/(3x) is diverges