What is the sum from n=0 to infinity of 1/(1.01^n) ?

The sum from n=0 to infinity of 1/(1.01^n) is 101

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sum from n=0 to infinity of 1/(1.01^n)

n = 0 \sum \infty \frac{1}{1.0 1 ^{n}}

101

Solution steps

n = 0 \sum \infty \frac{1}{1.0 1 ^{n}}

Apply Series Geometric Test:

101

= 101

\int_{1}^{\infty} x e^{- 8 x} d x

\frac{d}{d x} ((4 x - 1)^{2})

y = x^{2}, y = 2 x^{2} - 4 x, y = 0

\int \frac{x ^{2}}{( x ^{2} + 8 ) ^{\frac{3}{2}}} d x

\frac{d r}{d θ} = π

What is the sum from n=0 to infinity of 1/(1.01^n) ?
The sum from n=0 to infinity of 1/(1.01^n) is 101