What is the derivative of f(t)=cos^2(e^{cos^2(t)}) ?

The derivative of f(t)=cos^2(e^{cos^2(t)}) is e^{cos^2(t)}sin(2e^{cos^2(t)})sin(2t)

What is the first derivative of f(t)=cos^2(e^{cos^2(t)}) ?

The first derivative of f(t)=cos^2(e^{cos^2(t)}) is e^{cos^2(t)}sin(2e^{cos^2(t)})sin(2t)

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derivative of

f (t) = cos^{2} (e^{c o s^{2} (t)})

e^{c o s^{2} (t)} sin (2 e^{c o s^{2} (t)}) sin (2 t)

Solution steps

\frac{d}{d t} (cos^{2} (e^{c o s^{2} (t)}))

Apply the chain rule:

2 cos (e^{c o s^{2} (t)}) \frac{d}{d t} (cos (e^{c o s^{2} (t)}))

= 2 cos (e^{c o s^{2} (t)}) \frac{d}{d t} (cos (e^{c o s^{2} (t)}))

\frac{d}{d t} (cos (e^{c o s^{2} (t)})) = e^{c o s^{2} (t)} sin (e^{c o s^{2} (t)}) sin (2 t)

= 2 cos (e^{c o s^{2} (t)}) e^{c o s^{2} (t)} sin (e^{c o s^{2} (t)}) sin (2 t)

Use the Double Angle identity:

2 sin (x) cos (x) = sin (2 x)

= e^{c o s^{2} (t)} sin (2 e^{c o s^{2} (t)}) sin (2 t)

\int \frac{19}{x ^{2} + 1} d x

\frac{\partial}{\partial x} (7 e^{x})

\int \frac{x}{x - 2} d x

y^{^{'}} = \frac{x - 2}{y + 1}

\int - ∣ x ∣^{2} d x

What is the derivative of f(t)=cos^2(e^{cos^2(t)}) ?
The derivative of f(t)=cos^2(e^{cos^2(t)}) is e^{cos^2(t)}sin(2e^{cos^2(t)})sin(2t)
What is the first derivative of f(t)=cos^2(e^{cos^2(t)}) ?
The first derivative of f(t)=cos^2(e^{cos^2(t)}) is e^{cos^2(t)}sin(2e^{cos^2(t)})sin(2t)