en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

v'=-0.01v^2

Solution

v^{'} = - 0.01 v^{2}

Solution

v = 0

Solution steps

v^{'} = - 0.01 v^{2}

v^{'} = 0

0 = - 0.01 v^{2}

0 = - 0.01 v^{2} : v = 0

v = 0

Popular Examples

y^{''}+2y^'+2y=sin(1t)

y^{^{''}} + 2 y^{^{'}} + 2 y = sin (1 t)

limit as x approaches 5 of-2

x \to 5 lim (- 2)

inverse oflaplace 6/((s-2)^4)inverse laplace

\frac{6}{( s - 2 ) ^{4}}

derivative of f(x)=x^2+8 derivative of

f (x) = x^{2} + 8

integral of 4x^{1/3}-4x^{-1/3}

\int 4 x^{\frac{1}{3}} - 4 x^{- \frac{1}{3}} d x

Frequently Asked Questions (FAQ)

What is v'=-0.01v^2 ?
The answer to v'=-0.01v^2 is v=0