What is the derivative of f(x)=x^2+8 ?

The derivative of f(x)=x^2+8 is 2x

What is the first derivative of f(x)=x^2+8 ?

The first derivative of f(x)=x^2+8 is 2x

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derivative of

f (x) = x^{2} + 8

2 x

Solution steps

\frac{d}{d x} (x^{2} + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (8) = 0

= 2 x + 0

Simplify

= 2 x

\int 4 x^{\frac{1}{3}} - 4 x^{- \frac{1}{3}} d x

\int - (sin (x))^{2} d x

f (t) = 2 sin^{2} (t)

\int_{- π}^{π} cos^{2} (5 x) d x

x \to \frac{π}{2} + lim (\frac{1}{x} sec (x))

What is the derivative of f(x)=x^2+8 ?
The derivative of f(x)=x^2+8 is 2x
What is the first derivative of f(x)=x^2+8 ?
The first derivative of f(x)=x^2+8 is 2x