What is the integral of-(sin(x))^2 ?

The integral of-(sin(x))^2 is -1/2 (x-1/2 sin(2x))+C

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integral of-(sin(x))^2

\int - (sin (x))^{2} d x

- \frac{1}{2} (x - \frac{1}{2} sin (2 x)) + C

Solution steps

\int - (sin (x))^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int (sin (x))^{2} d x

Simplify

= - \int sin^{2} (x) d x

Rewrite using trig identities

= - \int \frac{1 - cos ( 2 x )}{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int 1 - cos (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \frac{1}{2} (\int 1 d x - \int cos (2 x) d x)

\int 1 d x = x

\int cos (2 x) d x = \frac{1}{2} sin (2 x)

= - \frac{1}{2} (x - \frac{1}{2} sin (2 x))

Add a constant to the solution

= - \frac{1}{2} (x - \frac{1}{2} sin (2 x)) + C

f (t) = 2 sin^{2} (t)

\int_{- π}^{π} cos^{2} (5 x) d x

x \to \frac{π}{2} + lim (\frac{1}{x} sec (x))

\int sec (38 w) tan (38 w) d w

x \to 1 lim (∣ x - 2 ∣)

What is the integral of-(sin(x))^2 ?
The integral of-(sin(x))^2 is -1/2 (x-1/2 sin(2x))+C