What is the first derivative of 2x^2+7 ?

The first derivative of 2x^2+7 is 4x

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derivative of 2x^2+7

\frac{d}{d x} (2 x^{2} + 7)

4 x

Solution steps

\frac{d}{d x} (2 x^{2} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) + \frac{d}{d x} (7)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (7) = 0

= 4 x + 0

Simplify

= 4 x

f (x) = (4 x + 5) (5 x - 1), at x = 3

\int 25 e^{- 5 x} sin (5 x) d x

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\frac{d}{d x} (x, (x))