What is the derivative of e^x-2cos(x) ?

The derivative of e^x-2cos(x) is e^x+2sin(x)

What is the first derivative of e^x-2cos(x) ?

The first derivative of e^x-2cos(x) is e^x+2sin(x)

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\frac{d}{d x} (e^{x} - 2 cos (x))

e^{x} + 2 sin (x)

Solution steps

\frac{d}{d x} (e^{x} - 2 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{x}) - \frac{d}{d x} (2 cos (x))

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

= e^{x} - (- 2 sin (x))

Simplify

= e^{x} + 2 sin (x)

\frac{\partial}{\partial x} (4 x^{- \frac{1}{2}} - \frac{6}{x})

\frac{\partial}{\partial x} (ln (9 + x^{2} + 3 y^{2}))

\frac{d}{d x} (\frac{6}{( x - 1 ) ^{4}})

\frac{d}{d x} (sin (x^{2} + 2))

\frac{d}{d x} (\frac{sin ( x )}{( x + 1 ) ^{2}})

What is the derivative of e^x-2cos(x) ?
The derivative of e^x-2cos(x) is e^x+2sin(x)
What is the first derivative of e^x-2cos(x) ?
The first derivative of e^x-2cos(x) is e^x+2sin(x)