What is the derivative of 6/((x-1^4)) ?

The derivative of 6/((x-1^4)) is -(24)/((x-1)^5)

What is the first derivative of 6/((x-1^4)) ?

The first derivative of 6/((x-1^4)) is -(24)/((x-1)^5)

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\frac{d}{d x} (\frac{6}{( x - 1 ) ^{4}})

- \frac{24}{( x - 1 ) ^{5}}

Solution steps

\frac{d}{d x} (\frac{6}{( x - 1 ) ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{1}{( x - 1 ) ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 6 \frac{d}{d x} ((x - 1)^{- 4})

Apply the chain rule:

- \frac{4}{( x - 1 ) ^{5}} \frac{d}{d x} (x - 1)

= - \frac{4}{( x - 1 ) ^{5}} \frac{d}{d x} (x - 1)

\frac{d}{d x} (x - 1) = 1

= 6 (- \frac{4}{( x - 1 ) ^{5}} \cdot 1)

Simplify

6 (- \frac{4}{( x - 1 ) ^{5}} \cdot 1) : - \frac{24}{( x - 1 ) ^{5}}

= - \frac{24}{( x - 1 ) ^{5}}

\frac{d}{d x} (sin (x^{2} + 2))

\frac{d}{d x} (\frac{sin ( x )}{( x + 1 ) ^{2}})

\frac{\partial}{\partial x} (x^{2} + 8)

\int cot (x) ln (x) sin (x) d x

\frac{d}{d x} (x^{x^{x^{x^{x}}}})

What is the derivative of 6/((x-1^4)) ?
The derivative of 6/((x-1^4)) is -(24)/((x-1)^5)
What is the first derivative of 6/((x-1^4)) ?
The first derivative of 6/((x-1^4)) is -(24)/((x-1)^5)