What is the integral of cot(x)ln(x)sin(x) ?

The integral of cot(x)ln(x)sin(x) is ln(x)sin(x)-\Si(x)+C

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integral of cot(x)ln(x)sin(x)

\int cot (x) ln (x) sin (x) d x

ln (x) sin (x) - Si (x) + C

Solution steps

\int cot (x) ln (x) sin (x) d x

Rewrite using trig identities

= \int cos (x) ln (x) d x

Apply Integration By Parts

: ln (x) sin (x) - \int \frac{sin ( x )}{x} d x

= ln (x) sin (x) - \int \frac{sin ( x )}{x} d x

\int \frac{sin ( x )}{x} d x = Si (x)

= ln (x) sin (x) - Si (x)

Add a constant to the solution

= ln (x) sin (x) - Si (x) + C

\frac{d}{d x} (x^{x^{x^{x^{x}}}})

\int \frac{x ^{3} - 1}{x - 1} d x

\int (\frac{sin ( x )}{cos ^{2} ( x )}) d x

n = 2 \sum \infty \frac{8}{4 ^{2 n}}

y^{^{'}} = \frac{- 2 x y}{1 + x ^{2}}

What is the integral of cot(x)ln(x)sin(x) ?
The integral of cot(x)ln(x)sin(x) is ln(x)sin(x)-\Si(x)+C