What is the solution for (24+x^2)y^'-2xy=0 ?

The solution for (24+x^2)y^'-2xy=0 is y=24e^{c_{1}}+e^{c_{1}}x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(24+x^2)y^'-2xy=0

(24 + x^{2}) y^{^{'}} - 2 x y = 0

y = 24 e^{c_{1}} + e^{c_{1}} x^{2}

Solution steps

(24 + x^{2}) y^{'} (x) - 2 x y = 0

Solve separable ODE:

y = 24 e^{c_{1}} + e^{c_{1}} x^{2}

y = 24 e^{c_{1}} + e^{c_{1}} x^{2}

\frac{d y}{d x} = \frac{y ^{3}}{x}, y (1) = 1

\int \frac{x ^{2} - 5 x + 9}{x ^{2} - 5 x + 6} d x

\frac{\partial}{\partial x} (x, y, z)

x^{3}, 0, 3

f (x) = \frac{2 ln ( x )}{x}, at x = e

What is the solution for (24+x^2)y^'-2xy=0 ?
The solution for (24+x^2)y^'-2xy=0 is y=24e^{c_{1}}+e^{c_{1}}x^2