What is the integral from 3 to 4 of 9x ?

The integral from 3 to 4 of 9x is 63/2

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integral from 3 to 4 of 9x

\int_{3}^{4} 9 x d x

\frac{63}{2}

Decimal Notation

31.5

Solution steps

\int_{3}^{4} 9 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{3}^{4} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{3}^{4}

= 9 [\frac{x ^{2}}{2}]_{3}^{4}

Compute the boundaries:

\frac{7}{2}

= 9 \cdot \frac{7}{2}

Simplify

= \frac{63}{2}

\int \frac{3 x ^{2} - 4 x + 5}{( x - 1 ) ( x ^{2} + 1 )} d x

\frac{d}{d x} ((sin (2 x))^{x})

\int 3 (5^{1 - 2 x}) d x

\frac{d}{d x} (40 x)

x \to - 2 lim (3 x - 1)