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Popular >

y^'+2y=1

Solution

y^{^{'}} + 2 y = 1

Solution

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{1}{2}

Solution steps

y^{'} (t) + 2 y = 1

Solve separable ODE:

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{1}{2}

y = - \frac{e ^{- 2 t - c_{1}}}{2} + \frac{1}{2}

Popular Examples

16y^{''}+40y^'+25y=0

16 y^{^{''}} + 40 y^{^{'}} + 25 y = 0

integral of (x+4)e^{x^2+8x}

\int (x + 4) e^{x^{2} + 8 x} d x

(6x+1)y^2((dy)/(dx))+3x^2+2y^3=0

(6 x + 1) y^{2} (\frac{d y}{d x}) + 3 x^{2} + 2 y^{3} = 0

derivative of y=x^2cos(x)derivative of

y = x^{2} cos (x)

(dy)/(dx)=4xsqrt(4-y^2)

\frac{d y}{d x} = 4 x 4 - y^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=1 ?
The solution for y^'+2y=1 is y=-(e^{-2t-c_{1}})/2+1/2