What is the solution for (6x+1)y^2((dy)/(dx))+3x^2+2y^3=0 ?

The solution for (6x+1)y^2((dy)/(dx))+3x^2+2y^3=0 is y=\sqrt[3]{-(3x^3)/(6x+1)+(c_{1})/(6x+1)}

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(6x+1)y^2((dy)/(dx))+3x^2+2y^3=0

(6 x + 1) y^{2} (\frac{d y}{d x}) + 3 x^{2} + 2 y^{3} = 0

Solution steps

(6 x + 1) y^{2} (\frac{d y}{d x}) + 3 x^{2} + 2 y^{3} = 0

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What is the solution for (6x+1)y^2((dy)/(dx))+3x^2+2y^3=0 ?
The solution for (6x+1)y^2((dy)/(dx))+3x^2+2y^3=0 is y=\sqrt[3]{-(3x^3)/(6x+1)+(c_{1})/(6x+1)}