What is the integral from 4 to infinity of e^{-x/2} ?

The integral from 4 to infinity of e^{-x/2} is 2/(e^2)

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integral from 4 to infinity of e^{-x/2}

\int_{4}^{\infty} e^{- \frac{x}{2}} d x

\frac{2}{e ^{2}}

Decimal Notation

0.27067 \dots

Solution steps

\int_{4}^{\infty} e^{- \frac{x}{2}} d x

Compute the indefinite integral:

\int e^{- \frac{x}{2}} d x = - 2 e^{- \frac{x}{2}} + C

Compute the boundaries:

\int_{4}^{\infty} e^{- \frac{x}{2}} d x = 0 - (- \frac{2}{e ^{2}})

= 0 - (- \frac{2}{e ^{2}})

Simplify

= \frac{2}{e ^{2}}

\int \frac{ln ( x ) + 10}{x} d x

5 - x^{2}

\int_{- 2}^{2} \frac{1}{v} d v

x \to 0 + lim (x^{5 x})

y^{^{''}} - 9 y^{^{'}} + 18 y = e^{e^{- 3 x}}

What is the integral from 4 to infinity of e^{-x/2} ?
The integral from 4 to infinity of e^{-x/2} is 2/(e^2)