What is the integral of 1arcsin(x) ?

The integral of 1arcsin(x) is xarcsin(x)+sqrt(1-x^2)+C

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integral of 1arcsin(x)

\int 1 arcsin (x) d x

x arcsin (x) + 1 - x^{2} + C

Solution steps

\int 1 \cdot arcsin (x) d x

Simplify

= \int arcsin (x) d x

Apply Integration By Parts

: x arcsin (x) - \int \frac{x}{1 - x ^{2}} d x

= x arcsin (x) - \int \frac{x}{1 - x ^{2}} d x

\int \frac{x}{1 - x ^{2}} d x = - 1 - x^{2}

= x arcsin (x) - (- 1 - x^{2})

Simplify

= x arcsin (x) + 1 - x^{2}

Add a constant to the solution

= x arcsin (x) + 1 - x^{2} + C

\frac{\partial}{\partial x} (\frac{x}{1 + y ^{2}})

\int \frac{7}{x ^{2} - 2 x} d x

\frac{d}{d t} (3 t e^{- t})

b \to - 3 lim (\frac{b + 1}{b + 3})

y = x^{8} e^{x}

What is the integral of 1arcsin(x) ?
The integral of 1arcsin(x) is xarcsin(x)+sqrt(1-x^2)+C