What is the derivative of g(t)=6sqrt(t) ?

The derivative of g(t)=6sqrt(t) is 3/(sqrt(t))

What is the first derivative of g(t)=6sqrt(t) ?

The first derivative of g(t)=6sqrt(t) is 3/(sqrt(t))

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derivative of

g (t) = 6 t

\frac{3}{t}

Solution steps

\frac{d}{d t} (6 t)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d t} (t)

Apply radical rule:

a = a^{\frac{1}{2}}

= 6 \frac{d}{d t} (t^{\frac{1}{2}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 \cdot \frac{1}{2} t^{\frac{1}{2} - 1}

Simplify

6 \cdot \frac{1}{2} t^{\frac{1}{2} - 1} : \frac{3}{t}

= \frac{3}{t}

\frac{d}{d x} (\frac{2}{x ^{3}} + \frac{5}{x ^{2}})

\int x 4 x - 1 d x

\frac{d y}{d x}, 6 e^{x y} - x = 0

\frac{e ^{x}}{x ^{2} + 14}

\int_{1}^{2} \frac{7}{x ^{3} + 4 x} d x

What is the derivative of g(t)=6sqrt(t) ?
The derivative of g(t)=6sqrt(t) is 3/(sqrt(t))
What is the first derivative of g(t)=6sqrt(t) ?
The first derivative of g(t)=6sqrt(t) is 3/(sqrt(t))