What is the derivative of (2-sec(x))/(tan(x)) ?

The derivative of (2-sec(x))/(tan(x)) is (-tan^2(x)sec(x)-sec^2(x)(2-sec(x)))/(tan^2(x))

What is the first derivative of (2-sec(x))/(tan(x)) ?

The first derivative of (2-sec(x))/(tan(x)) is (-tan^2(x)sec(x)-sec^2(x)(2-sec(x)))/(tan^2(x))

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derivative of

\frac{2 - sec ( x )}{tan ( x )}

\frac{- tan ^{2} ( x ) sec ( x ) - sec ^{2} ( x ) ( 2 - sec ( x ) )}{tan ^{2} ( x )}

Solution steps

\frac{d}{d x} (\frac{2 - sec ( x )}{tan ( x )})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 - sec ( x ) ) tan ( x ) - \frac{d}{d x} ( tan ( x ) ) ( 2 - sec ( x ) )}{( tan ( x ) ) ^{2}}

\frac{d}{d x} (2 - sec (x)) = - sec (x) tan (x)

\frac{d}{d x} (tan (x)) = sec^{2} (x)

= \frac{( - sec ( x ) tan ( x ) ) tan ( x ) - sec ^{2} ( x ) ( 2 - sec ( x ) )}{( tan ( x ) ) ^{2}}

Simplify

\frac{( - sec ( x ) tan ( x ) ) tan ( x ) - sec ^{2} ( x ) ( 2 - sec ( x ) )}{tan ^{2} ( x )} : \frac{- tan ^{2} ( x ) sec ( x ) - sec ^{2} ( x ) ( 2 - sec ( x ) )}{tan ^{2} ( x )}

= \frac{- tan ^{2} ( x ) sec ( x ) - sec ^{2} ( x ) ( 2 - sec ( x ) )}{tan ^{2} ( x )}

\int e^{x} 15 + e^{x} d x

\frac{d}{d x} (\frac{3}{8} (x^{\frac{4}{3}} - 2 x^{\frac{2}{3}}))

\frac{d}{d x} (- sin (5 π x) \cdot 5 π)

\frac{d}{d x} ((x^{3} + 2)^{2} (x^{4} + 4)^{4})

y^{^{'}} (t) = 0.3 y \cdot (1 - \frac{y}{2500}) - \frac{y}{4}, y (0) = 600

What is the derivative of (2-sec(x))/(tan(x)) ?
The derivative of (2-sec(x))/(tan(x)) is (-tan^2(x)sec(x)-sec^2(x)(2-sec(x)))/(tan^2(x))
What is the first derivative of (2-sec(x))/(tan(x)) ?
The first derivative of (2-sec(x))/(tan(x)) is (-tan^2(x)sec(x)-sec^2(x)(2-sec(x)))/(tan^2(x))