What is the derivative of 1/(x^n) ?

The derivative of 1/(x^n) is -nx^{-n-1}

What is the first derivative of 1/(x^n) ?

The first derivative of 1/(x^n) is -nx^{-n-1}

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\frac{d}{d x} (\frac{1}{x ^{n}})

- n x^{- n - 1}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{n}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- n})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - n x^{- n - 1}

y = \frac{4 x ^{2} + 4 x + 8}{x}

\int_{0}^{8} x^{2} d x

\frac{\partial}{\partial x} (y - x^{2} - 7 z^{2})

f (x) = x^{2} + 8, at x = 2

\int e^{x} + 2 d x

What is the derivative of 1/(x^n) ?
The derivative of 1/(x^n) is -nx^{-n-1}
What is the first derivative of 1/(x^n) ?
The first derivative of 1/(x^n) is -nx^{-n-1}