What is (\partial)/(\partial x)(y-x^2-7z^2) ?

The answer to (\partial)/(\partial x)(y-x^2-7z^2) is -2x

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(\partial)/(\partial x)(y-x^2-7z^2)

\frac{\partial}{\partial x} (y - x^{2} - 7 z^{2})

- 2 x

Solution steps

\frac{\partial}{\partial x} (y - x^{2} - 7 z^{2})

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (7 z^{2})

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (7 z^{2}) = 0

= 0 - 2 x - 0

Simplify

= - 2 x

f (x) = x^{2} + 8, at x = 2

\int e^{x} + 2 d x

x \to - \infty lim (x^{2} + 6)

\frac{d}{d x} ((x^{4} + 3 x^{2} - 2)^{5})

\int \frac{( 3 y - 8 )}{y ^{2} - 4 y - 5} d y

What is (\partial)/(\partial x)(y-x^2-7z^2) ?
The answer to (\partial)/(\partial x)(y-x^2-7z^2) is -2x