What is the derivative of 1/((-3x^2+3x-2^3)) ?

The derivative of 1/((-3x^2+3x-2^3)) is -(3(-6x+3))/((-3x^2+3x-2)^4)

What is the first derivative of 1/((-3x^2+3x-2^3)) ?

The first derivative of 1/((-3x^2+3x-2^3)) is -(3(-6x+3))/((-3x^2+3x-2)^4)

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\frac{d}{d x} (\frac{1}{( - 3 x ^{2} + 3 x - 2 ) ^{3}})

- \frac{3 ( - 6 x + 3 )}{( - 3 x ^{2} + 3 x - 2 ) ^{4}}

Solution steps

\frac{d}{d x} (\frac{1}{( - 3 x ^{2} + 3 x - 2 ) ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((- 3 x^{2} + 3 x - 2)^{- 3})

Apply the chain rule:

- \frac{3}{( - 3 x ^{2} + 3 x - 2 ) ^{4}} \frac{d}{d x} (- 3 x^{2} + 3 x - 2)

= - \frac{3}{( - 3 x ^{2} + 3 x - 2 ) ^{4}} \frac{d}{d x} (- 3 x^{2} + 3 x - 2)

\frac{d}{d x} (- 3 x^{2} + 3 x - 2) = - 6 x + 3

= - \frac{3}{( - 3 x ^{2} + 3 x - 2 ) ^{4}} (- 6 x + 3)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{3 ( - 6 x + 3 )}{( - 3 x ^{2} + 3 x - 2 ) ^{4}}

\int - 2 x^{3} (- 5 x^{2} - x + 12) d x

\frac{\partial}{\partial z} (- 2 e^{x} cos (yz))

\int x^{3} (1 + x^{4})^{3} d x

\frac{d}{d x} (sin (x + 2))

\int_{- \infty}^{0} \frac{1}{4 - 3 x} d x

What is the derivative of 1/((-3x^2+3x-2^3)) ?
The derivative of 1/((-3x^2+3x-2^3)) is -(3(-6x+3))/((-3x^2+3x-2)^4)
What is the first derivative of 1/((-3x^2+3x-2^3)) ?
The first derivative of 1/((-3x^2+3x-2^3)) is -(3(-6x+3))/((-3x^2+3x-2)^4)