What is the integral from-infinity to 0 of 1/(4-3x) ?

The integral from-infinity to 0 of 1/(4-3x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 0 of 1/(4-3x)

\int_{- \infty}^{0} \frac{1}{4 - 3 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{4 - 3 x} d x

Compute the indefinite integral:

\int \frac{1}{4 - 3 x} d x = - \frac{1}{3} ln ∣ 4 - 3 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{4 - 3 x} d x =

diverges

= diverges

\frac{s}{( s - 3 ) ^{3}}

\frac{\partial}{\partial y} (ln (2 x^{2} + 3 y^{2}))

\frac{d}{d x} (\frac{A}{x ^{9}} + B e^{x})

(4 + x) y^{^{'}} = 8 y

\int (x^{2} - 7 x + 2) d x

What is the integral from-infinity to 0 of 1/(4-3x) ?
The integral from-infinity to 0 of 1/(4-3x) is diverges