What is the integral from-pi to pi of sin(kx)cos(nx) ?

The integral from-pi to pi of sin(kx)cos(nx) is 0

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integral from-pi to pi of sin(kx)cos(nx)

\int_{- π}^{π} sin (k x) cos (n x) d x

0

Solution steps

\int_{- π}^{π} sin (k x) cos (n x) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

sin (k x) cos (n x) :

Odd

= 0

x^{^{'}} = a x - b x^{2}

x \to - 1 lim (\frac{f ( x )}{x + 1})

y^{^{'}} = \frac{- x y ^{2}}{2}

\int \frac{1}{N} d N

\int (\frac{1}{y ^{2}}) d y

What is the integral from-pi to pi of sin(kx)cos(nx) ?
The integral from-pi to pi of sin(kx)cos(nx) is 0