What is (\partial)/(\partial x)(x+3*ln(x)-y^2) ?

The answer to (\partial)/(\partial x)(x+3*ln(x)-y^2) is 3/x+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x+3*ln(x)-y^2)

\frac{\partial}{\partial x} (x + 3 \cdot ln (x) - y^{2})

\frac{3}{x} + 1

Solution steps

\frac{\partial}{\partial x} (x + 3 ln (x) - y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (3 ln (x)) - \frac{\partial}{\partial x} (y^{2})

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (3 ln (x)) = \frac{3}{x}

\frac{\partial}{\partial x} (y^{2}) = 0

= 1 + \frac{3}{x} - 0

Simplify

= \frac{3}{x} + 1

\frac{d}{d x} (a x^{2} + x)

\int_{5}^{6} \frac{1}{x ^{2} - 1} d x

\int_{- 2}^{3} \frac{18}{x ^{4}} d x

x^{2} + 7

\frac{\partial}{\partial x} (3 x^{2} + 5 y^{3})

What is (\partial)/(\partial x)(x+3*ln(x)-y^2) ?
The answer to (\partial)/(\partial x)(x+3*ln(x)-y^2) is 3/x+1