What is the first derivative of x^2+7 ?

The first derivative of x^2+7 is 2x

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derivative of x^2+7

derivative of

x^{2} + 7

2 x

Solution steps

\frac{d}{d x} (x^{2} + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (7) = 0

= 2 x + 0

Simplify

= 2 x

\frac{\partial}{\partial x} (3 x^{2} + 5 y^{3})

y^{^{'}} + \frac{y}{t} = 3 cos (4 t)

y^{^{'}} + y + y^{2} = 0

\frac{d}{d x} (ln (1 + 4 x))

(- 10, - 8), (- 8, - 16)