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Popular >

y^'+y+y^2=0

Solution

y^{^{'}} + y + y^{2} = 0

Solution

y = - \frac{1}{1 - e ^{t + c_{1}}}

Solution steps

y^{'} (t) + y + y^{2} = 0

Solve separable ODE:

y = - \frac{1}{1 - e ^{t + c_{1}}}

y = - \frac{1}{1 - e ^{t + c_{1}}}

Popular Examples

derivative of ln(1+4x)

\frac{d}{d x} (ln (1 + 4 x))

slope of (-10,-8),(-8,-16)slope

(- 10, - 8), (- 8, - 16)

derivative of 3e^{5x}

\frac{d}{d x} (3 e^{5 x})

area x=y^2,y=x-2 area

x = y^{2}, y = x - 2

limit as x approaches 0 of |x|x

x \to 0 lim (∣ x ∣ x)

Frequently Asked Questions (FAQ)

What is the solution for y^'+y+y^2=0 ?
The solution for y^'+y+y^2=0 is y=-1/(1-e^{t+c_{1)}}