What is the derivative of y=x^4-2x^3-9 ?

The derivative of y=x^4-2x^3-9 is 4x^3-6x^2

What is the first derivative of y=x^4-2x^3-9 ?

The first derivative of y=x^4-2x^3-9 is 4x^3-6x^2

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derivative of

y = x^{4} - 2 x^{3} - 9

4 x^{3} - 6 x^{2}

Solution steps

\frac{d}{d x} (x^{4} - 2 x^{3} - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (9)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (9) = 0

= 4 x^{3} - 6 x^{2} - 0

Simplify

= 4 x^{3} - 6 x^{2}

\int (x - 1) d x

x \to 0 lim (\frac{x}{1 - x})

\frac{\partial}{\partial x} (sin (x - 3 y))

\int_{- 1}^{0} (x + 2)^{13} d x

\int_{0}^{\infty} - e^{- x} d x

What is the derivative of y=x^4-2x^3-9 ?
The derivative of y=x^4-2x^3-9 is 4x^3-6x^2
What is the first derivative of y=x^4-2x^3-9 ?
The first derivative of y=x^4-2x^3-9 is 4x^3-6x^2