What is (\partial)/(\partial x)(-ln(x)) ?

The answer to (\partial)/(\partial x)(-ln(x)) is -1/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(-ln(x))

\frac{\partial}{\partial x} (- ln (x))

- \frac{1}{x}

Solution steps

\frac{\partial}{\partial x} (- ln (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial x} (ln (x))

Apply the common derivative:

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

= - \frac{1}{x}

\int \frac{14}{2 x + x x} d x

y^{^{''}} + 4 y^{^{'}} + 4 y = x cos (2 x)

y^{^{''}} + y^{^{'}} + y = 1

\frac{\partial}{\partial x} (- x y^{2} z^{3} - 4 x yz)

n = 1 \sum \infty sin^{n} (2)

What is (\partial)/(\partial x)(-ln(x)) ?
The answer to (\partial)/(\partial x)(-ln(x)) is -1/x