What is the derivative of 4cos(3x) ?

The derivative of 4cos(3x) is -12sin(3x)

What is the first derivative of 4cos(3x) ?

The first derivative of 4cos(3x) is -12sin(3x)

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\frac{d}{d x} (4 cos (3 x))

- 12 sin (3 x)

Solution steps

\frac{d}{d x} (4 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 4 (- sin (3 x) \cdot 3)

Simplify

= - 12 sin (3 x)

\int_{1}^{2} tan (x y) d y

\frac{d}{d x} (8 x^{4} + 5 x^{3} - x^{2} + 4 x - 1)

- 7 (t - 4)

\frac{d}{d x} (x (2 x + 1)^{5})

\frac{d y}{d x} = 5 y + y^{2}

What is the derivative of 4cos(3x) ?
The derivative of 4cos(3x) is -12sin(3x)
What is the first derivative of 4cos(3x) ?
The first derivative of 4cos(3x) is -12sin(3x)