What is (\partial)/(\partial x)(sin(2x+y)) ?

The answer to (\partial)/(\partial x)(sin(2x+y)) is cos(2x+y)*2

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(\partial)/(\partial x)(sin(2x+y))

\frac{\partial}{\partial x} (sin (2 x + y))

cos (2 x + y) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (2 x + y))

Treat

y

as a constant

Apply the chain rule:

cos (2 x + y) \frac{\partial}{\partial x} (2 x + y)

= cos (2 x + y) \frac{\partial}{\partial x} (2 x + y)

\frac{\partial}{\partial x} (2 x + y) = 2

= cos (2 x + y) \cdot 2

\frac{d}{d x} (- (x - 3)^{2})

\frac{d}{d x} (- x csc^{2} (x))

n = 1 \sum \infty \frac{3}{e ^{n}}

\int \frac{1}{x ^{2} + 2 x + 10} d x

\int x (2 + x^{2})^{3} d x

What is (\partial)/(\partial x)(sin(2x+y)) ?
The answer to (\partial)/(\partial x)(sin(2x+y)) is cos(2x+y)*2