What is the integral from 0 to pi/2 of (cos(x)) ?

The integral from 0 to pi/2 of (cos(x)) is 1

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integral from 0 to pi/2 of (cos(x))

\int_{0}^{\frac{π}{2}} (cos (x)) d x

1

Solution steps

\int_{0}^{\frac{π}{2}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 1

\int \frac{11}{12} x^{2} + \frac{1}{12} x d x

\frac{d}{d t} (sin (t))

\int (1 - \frac{1}{x}) d x

\frac{\partial}{\partial t} (e^{- 2 t})

\int x^{4} - 6 x d x

What is the integral from 0 to pi/2 of (cos(x)) ?
The integral from 0 to pi/2 of (cos(x)) is 1