What is the derivative of y=sqrt(ln(x)) ?

The derivative of y=sqrt(ln(x)) is 1/(2xsqrt(ln(x)))

What is the first derivative of y=sqrt(ln(x)) ?

The first derivative of y=sqrt(ln(x)) is 1/(2xsqrt(ln(x)))

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derivative of

y = ln (x)

\frac{1}{2 x ln ( x )}

Solution steps

\frac{d}{d x} (ln (x))

Apply the chain rule:

\frac{1}{2 ln ( x )} \frac{d}{d x} (ln (x))

= \frac{1}{2 ln ( x )} \frac{d}{d x} (ln (x))

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= \frac{1}{2 ln ( x )} \cdot \frac{1}{x}

Simplify

\frac{1}{2 ln ( x )} \cdot \frac{1}{x} : \frac{1}{2 x ln ( x )}

= \frac{1}{2 x ln ( x )}

y = x^{2} - 4 x, y = - x^{2}

\int x^{2} - 3 x - 4 d x

x \to - 2 + lim (\frac{x}{x ^{2} - 3 x - 10})

y = \frac{x}{10} - \frac{10}{x}

\int \frac{( cos ^{2} ( a t ) )}{a} d x

What is the derivative of y=sqrt(ln(x)) ?
The derivative of y=sqrt(ln(x)) is 1/(2xsqrt(ln(x)))
What is the first derivative of y=sqrt(ln(x)) ?
The first derivative of y=sqrt(ln(x)) is 1/(2xsqrt(ln(x)))