What is the integral from 1 to 3 of 2\sqrt[4]{x^3} ?

The integral from 1 to 3 of 2\sqrt[4]{x^3} is (2(12*3^{3/4}-4))/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of 2\sqrt[4]{x^3}

\frac{2 ( 12 \cdot 3 ^{\frac{3}{4}} - 4 )}{7}

Decimal Notation

6.67259 \dots

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= 2 \cdot \int_{1}^{3} x^{\frac{3}{4}} d x

Apply the Power Rule

: [\frac{4}{7} x^{\frac{7}{4}}]_{1}^{3}

= 2 [\frac{4}{7} x^{\frac{7}{4}}]_{1}^{3}

Compute the boundaries:

\frac{12 \cdot 3 ^{\frac{3}{4}}}{7} - \frac{4}{7}

= 2 (\frac{12 \cdot 3 ^{\frac{3}{4}}}{7} - \frac{4}{7})

Simplify

= \frac{2 ( 12 \cdot 3 ^{\frac{3}{4}} - 4 )}{7}

y^{^{'}} = (1 + x) (1 + y^{2})

\int e^{(- 2 x)} d x

\int_{- 1}^{2} (y + 2) - y^{2} d y

\int x y e^{x z} d z

\frac{\partial}{\partial z} (e^{c o s (x^{2})})

What is the integral from 1 to 3 of 2\sqrt[4]{x^3} ?
The integral from 1 to 3 of 2\sqrt[4]{x^3} is (2(12*3^{3/4}-4))/7