What is the derivative of y=ln(3x-7) ?

The derivative of y=ln(3x-7) is 3/(3x-7)

What is the first derivative of y=ln(3x-7) ?

The first derivative of y=ln(3x-7) is 3/(3x-7)

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derivative of

y = ln (3 x - 7)

\frac{3}{3 x - 7}

Solution steps

\frac{d}{d x} (ln (3 x - 7))

Apply the chain rule:

\frac{1}{3 x - 7} \frac{d}{d x} (3 x - 7)

= \frac{1}{3 x - 7} \frac{d}{d x} (3 x - 7)

\frac{d}{d x} (3 x - 7) = 3

= \frac{1}{3 x - 7} \cdot 3

Simplify

\frac{1}{3 x - 7} \cdot 3 : \frac{3}{3 x - 7}

= \frac{3}{3 x - 7}

\int \frac{2 x ^{3} - x ^{2} + 2 x + 2}{x ^{2} + 1} d x

\frac{1}{x - 1}, 10

y^{^{''}} + π^{2} y = 2

2 x^{3} - 2 x^{2} + 12

x^{\frac{3}{8}}

What is the derivative of y=ln(3x-7) ?
The derivative of y=ln(3x-7) is 3/(3x-7)
What is the first derivative of y=ln(3x-7) ?
The first derivative of y=ln(3x-7) is 3/(3x-7)